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(D) According to the kinetic theory of gases,the average kinetic energy per molecule of an ideal gas is given by $E_{avg} = \frac{3}{2}kT$,where $k$ i

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$\frac{3RT}{2}$

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(D) According to the kinetic theory of gases,the average kinetic energy per molecule of an ideal gas is given by $E_{avg} = \frac{3}{2}kT$,where $k$ is the Boltzmann constant and $T$ is the absolute temperature.For $1$ mole of gas,the number of molecules is equal to Avogadro's number,$N_A$.Therefore,the total kinetic energy for $1$ mole is $E = N_A 	imes (\frac{3}{2}kT)$.Since $k = \frac{R}{N_A}$,we have $E = N_A 	imes \frac{3}{2} 	imes (\frac{R}{N_A}) 	imes T$.Simplifying this,we get $E = \frac{3}{2}RT$.Thus,the average kinetic energy of $1$ gram-mole (which is $1$ mole) of a gas is $\frac{3RT}{2}$.

According to the kinetic theory of gases,the average kinetic energy of $1$ gram-mole of a gas is given by which of the following expressions?

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