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(C) For a uniform triangular lamina,the center of mass is located at the centroid of the triangle.If the vertices of the right-angled triangle are at

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$\left( \frac{b}{3}, \frac{h}{3} \right)$

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(C) For a uniform triangular lamina,the center of mass is located at the centroid of the triangle.If the vertices of the right-angled triangle are at $(0, 0)$,$(b, 0)$,and $(0, h)$,the coordinates of the center of mass $(x_{cm}, y_{cm})$ are given by the average of the coordinates of the vertices:$x_{cm} = \frac{x_1 + x_2 + x_3}{3} = \frac{0 + b + 0}{3} = \frac{b}{3}$$y_{cm} = \frac{y_1 + y_2 + y_3}{3} = \frac{0 + 0 + h}{3} = \frac{h}{3}$Therefore,the coordinates of the center of mass are $\left( \frac{b}{3}, \frac{h}{3} \right)$.

The coordinates of the center of mass of the triangular lamina shown in the figure are ....... .

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