Which of the following represents the percent | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The percentage strength of a solution can be expressed in different ways depending on the physical states of the solute and solvent: $1$. Mass per

Vedclass · Accepted Answer

All of the above

Vedclass · Answer

(D) The percentage strength of a solution can be expressed in different ways depending on the physical states of the solute and solvent: $1$. Mass percentage $(w/w)$: $\frac{	ext{Weight of solute}}{	ext{Weight of solution}} 	imes 100$ $2$. Mass by volume percentage $(w/v)$: $\frac{	ext{Weight of solute}}{	ext{Volume of solution}} 	imes 100$ $3$. Volume percentage $(v/v)$: $\frac{	ext{Volume of solute}}{	ext{Volume of solution}} 	imes 100$ Since all these formulas represent valid ways to express the percentage concentration of a solution,the correct answer is $D$.

Which of the following represents the percentage strength of a solution?

Similar Questions

Find out the molality of a solution prepared by dissolving $2.89 \ g$ of $NaCl$ in $0.159 \ L$ of water. The density of water is $1.00 \ g / mL$. (in $m$)

$x$ grams of water is mixed in $69 \ g$ of ethanol. The mole fraction of ethanol in the resultant solution is $0.6$. What is the value of $x$ in grams?

The formula weight of $H_2SO_4$ is $98$. The weight of the acid in $400 \ mL$ of $0.1 \ M$ solution is ........... $g$.

Calculate the mass percentage of $3 \ g$ of solute $A$ dissolved in $18 \ g$ of water. (in $\%$)

$25 \ mL$ of $3.0 \ M \ HNO_3$ are mixed with $75 \ mL$ of $4.0 \ M \ HNO_3$. If the volumes are additive,the molarity of the final mixture would be ......... $M$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module