A radar has a power of 1 text{ kW} and operat | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The maximum line-of-sight distance $d_M$ for a transmitter at height $h$ above the Earth's surface is given by the formula:$d_M = \sqrt{2hR}$Given

Vedclass · Accepted Answer

$80$

Vedclass · Answer

(A) The maximum line-of-sight distance $d_M$ for a transmitter at height $h$ above the Earth's surface is given by the formula:$d_M = \sqrt{2hR}$Given:Height $h = 500 	ext{ m}$Earth's radius $R = 6.4 	imes 10^{6} 	ext{ m}$Substituting the values:$d_M = \sqrt{2 	imes 500 	imes 6.4 	imes 10^{6}}$$d_M = \sqrt{1000 	imes 6.4 	imes 10^{6}}$$d_M = \sqrt{6.4 	imes 10^{9}}$$d_M = \sqrt{6400 	imes 10^{6}}$$d_M = 80 	imes 10^{3} 	ext{ m}$$d_M = 80 	ext{ km}$Thus,the radar can detect objects up to a maximum distance of $80 	ext{ km}$.

Similar Questions

Which of the following is the communication channel in case of radio communication?

$A$ carrier is simultaneously modulated by two sine waves with modulation indices of $0.3$ and $0.4$; then the total modulation index is

What is a transducer?

In amplitude modulation,the amplitude of the carrier wave is $A_c$ and that of the modulating signal is $A_m$. In practice,the ratio of $A_m$ to $A_c$ is kept less than or equal to $1$ to avoid:

If in an amplitude modulated wave,the maximum amplitude is $14 \ V$ and the modulation index is $0.4$,then the amplitude of the carrier wave is (in $V$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module