The mathematical form of an AM wave is given | vedclass

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(B) The standard equation for an $AM$ wave is given by $e = E_c (1 + m_a \sin \omega_m t) \sin \omega_c t$. Comparing the given equation $e = 50 (1 +

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$50 \, V, 25 \, V$

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(B) The standard equation for an $AM$ wave is given by $e = E_c (1 + m_a \sin \omega_m t) \sin \omega_c t$. Comparing the given equation $e = 50 (1 + 0.5 \sin (2\pi 	imes 5 	imes 10^{3}) t) \sin (31.4 	imes 10^{6}) t$ with the standard form: The amplitude of the carrier wave is $E_c = 50 \, V$. The modulation index is $m_a = 0.5$. Since $m_a = \frac{E_m}{E_c}$,the amplitude of the modulating wave is $E_m = m_a 	imes E_c$. Substituting the values: $E_m = 0.5 	imes 50 = 25 \, V$. Thus,the carrier wave amplitude is $50 \, V$ and the modulating wave amplitude is $25 \, V$.

The mathematical form of an $AM$ wave is given by $e = 50 (1 + 0.5 \sin (2\pi \times 5 \times 10^{3}) t) \sin (31.4 \times 10^{6}) t \, V$. To generate this $AM$ wave,the amplitudes of the carrier wave and the modulating wave must be,respectively,....... and ....... .

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