According to the $PV$ diagram shown in the figure,a thermodynamic system is taken from state $A$ to state $B$ along the path $ACB$ and is brought back to state $A$ along the path $BDA$. The net work done during the complete cycle is given by the area of:

$A$ thermodynamic system is taken through the cycle $PQRSP$ process as shown in the figure. The net work done by the system is .... $J$. (Note: $1 \text{ kp} = 10^3 \text{ Pa}$,$1 \text{ cc} = 10^{-6} \text{ m}^3$)

$A$ gas takes part in two processes in which it is heated from the same initial state $1$ to the same final temperature. The processes are shown on the $P-V$ diagram by the straight lines $1-2$ and $1-3$. Points $2$ and $3$ lie on the same isothermal curve. If $Q_1$ and $Q_2$ are the heat transferred along the two processes,then:

In the given $PV$ diagram,a system goes from state $P$ to state $Q$ along two different paths. Along path $1$,the system is given $1000 \ J$ of heat. The work done by the system along path $1$ is $100 \ J$ more than the work done along path $2$. How much heat is transferred along path $2$ (in $J$)?

The process $AB$ is shown in the diagram. As the gas is taken from $A$ to $B$,its temperature

In the cyclic process shown on the $P-V$ diagram,the magnitude of the work done is