$A$ thermodynamic system is taken through the cycle $PQRSP$ process as shown in the figure. The net work done by the system is .... $J$. (Note: $1 \text{ kp} = 10^3 \text{ Pa}$,$1 \text{ cc} = 10^{-6} \text{ m}^3$)

  • A
    $20$
  • B
    $-20$
  • C
    $400$
  • D
    $-374$

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