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(D) According to the Work-Energy Theorem,the total work done on the block is equal to the change in its kinetic energy: $W_{total} = \Delta K$.Here,th

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$-1.96$

Vedclass · Answer

(D) According to the Work-Energy Theorem,the total work done on the block is equal to the change in its kinetic energy: $W_{total} = \Delta K$.Here,the total work is the sum of work done by gravity $(W_g)$ and work done by non-conservative forces like friction $(W_{nc})$.Since the block starts and ends at rest,$\Delta K = 0$.$W_g + W_{nc} = 0$.The work done by gravity is $W_g = mg \Delta h$,where $\Delta h$ is the vertical displacement.Given $m = 1 \ kg$,$g = 9.8 \ m/s^2$,and $\Delta h = 0.2 \ m$ (assuming $A$ is higher than $B$ by $0.2 \ m$ based on the context of sliding down).$W_g = 1 	imes 9.8 	imes 0.2 = 1.96 \ J$.Substituting this into the equation: $1.96 + W_{nc} = 0$.Therefore,$W_{nc} = -1.96 \ J$.

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