A body of mass 0.50 kg is moving on a smooth | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given: $m_1 = 0.50 \ kg$,$u_1 = 2.00 \ m/s$,$m_2 = 1.00 \ kg$,$u_2 = 0 \ m/s$.By the law of conservation of linear momentum: $m_1 u_1 + m_2 u_2 =

Vedclass · Accepted Answer

$0.67$

Vedclass · Answer

(C) Given: $m_1 = 0.50 \ kg$,$u_1 = 2.00 \ m/s$,$m_2 = 1.00 \ kg$,$u_2 = 0 \ m/s$.By the law of conservation of linear momentum: $m_1 u_1 + m_2 u_2 = (m_1 + m_2)v$.$(0.50)(2.00) + (1.00)(0) = (0.50 + 1.00)v$.$1.00 = 1.50v \implies v = \frac{1.00}{1.50} = \frac{2}{3} \ m/s$.Initial kinetic energy $K_i = \frac{1}{2} m_1 u_1^2 = \frac{1}{2} (0.50) (2.00)^2 = 1.00 \ J$.Final kinetic energy $K_f = \frac{1}{2} (m_1 + m_2) v^2 = \frac{1}{2} (1.50) (\frac{2}{3})^2 = 0.75 	imes \frac{4}{9} = 0.333... \ J$.Energy loss $\Delta K = K_i - K_f = 1.00 - 0.333 = 0.667 \ J \approx 0.67 \ J$.

$A$ body of mass $0.50 \ kg$ is moving on a smooth surface with a speed of $2.00 \ m/s$. It collides with another body of mass $1.00 \ kg$ at rest,and they move together as a single body. The energy loss during the collision is ....... $J$.

Similar Questions

$A$ body of mass $40 \ kg$ moves with a velocity of $4 \ m/s$,and another body of mass $60 \ kg$ moves with a velocity of $2 \ m/s$. If they undergo a perfectly inelastic collision,the loss in kinetic energy is $... \ J$.

$A$ metal ball of mass $2 \ kg$ moves with a speed of $36 \ km/hr$. It collides with a stationary ball of mass $3 \ kg$. If both balls move together after the collision,the loss in kinetic energy due to the collision is ........... $J$.

$A$ bullet weighing $10 \,g$ and moving with a velocity $300 \,m/s$ strikes a $5 \,kg$ block of ice and gets embedded in it. The ice block is kept on a smooth surface. The speed of the block after the collision is ........ $cm/s$.

$A$ block of mass $10 \text{ g}$ is suspended from the ceiling by a string. $A$ bullet of mass $10 \text{ g}$ moving with a velocity of $1 \text{ m/s}$ strikes the block and gets embedded in it. To what height will the block rise (in $\text{ cm}$)? (Take $g = 10 \text{ m/s}^2$)

$A$ bullet of mass $m$ moving with velocity $v$ strikes a block of mass $M$ and gets embedded in it. The kinetic energy of the system is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module