$A$ body of mass $10 \ kg$ moves a distance of $10 \ m$ with a constant velocity on a smooth inclined plane of angle $\theta = 30^\circ$. Calculate the work done by the force acting on the body in $J$. $[g = 10 \ m/s^2]$

Two bodies of masses $m_{1}=5\,kg$ and $m_{2}=3\,kg$ are connected by a light string going over a smooth light pulley on a smooth inclined plane as shown in the figure. The system is at rest. The force exerted by the inclined plane on the body of mass $m_{1}$ will be $....N$ [Take $g=10\,ms^{-2}$]

If $M_1 = M_2 = 5 \, kg$ and $\theta = 30^\circ$,then the tension in the string will be ........... $N$.

$A$ small block slides without friction down an inclined plane starting from rest. Let $S_n$ be the distance travelled from time $t = n - 1$ to $t = n$. Then $\frac{S_n}{S_{n+1}}$ is

Two masses $M_1$ and $M_2$ are attached to the ends of a light string which passes over a massless pulley attached to the top of a double inclined smooth plane of angles of inclination $\alpha$ and $\beta$. The tension in the string is:

In the figure shown,$A$ and $B$ are free to move. All the surfaces are smooth. Then for $(0 < \theta < 90^o)$: