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(A) This is a case of a perfectly inelastic collision where the bullet gets embedded in the sandbag on the truck.According to the law of conservation

Vedclass · Accepted Answer

$\frac{\mu}{M + m}$

Vedclass · Answer

(A) This is a case of a perfectly inelastic collision where the bullet gets embedded in the sandbag on the truck.According to the law of conservation of linear momentum, the total momentum before the collision must equal the total momentum after the collision.Let $V$ be the final velocity of the truck (with the bullet and sandbag) after the collision.Initial momentum of the system = $m \cdot u + M \cdot 0 = \mu$.Final momentum of the system = $(M + m) \cdot V$.Equating the two: $\mu = (M + m)V$.Solving for $V$: $V = \frac{\mu}{M + m}$.

$A$ bullet of mass $m$ is fired horizontally with a velocity $u$ into a sandbag placed on a truck. If the mass of the truck is $M$, what will be the velocity of the truck after the collision?

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