For the reaction $A + B \rightleftharpoons C + D$,the equilibrium constant is $K$. If the initial moles of $A$ and $B$ are $1.0 \ mol$ each,what will be the value of the equilibrium constant in a second experiment under the same conditions if the initial moles of $A$ and $B$ are $2 \ mol$ and $3 \ mol$ respectively?

  • A
    $K/2$
  • B
    $K$
  • C
    $K^2$
  • D
    $1/K$

Explore More

Similar Questions

In a chemical reaction,equilibrium is established when:

In which of the following reactions,the concentration of product is higher than the concentration of reactant at equilibrium? $(K = \text{equilibrium constant})$

$A$ chemical reaction is at equilibrium when

For the reaction $N_2 + 3H_2 \rightleftharpoons 2NH_3$,the value of $K_c$ does not depend on: $(a)$ Initial concentration of reactants $(b)$ Pressure $(c)$ Temperature $(d)$ Catalyst

Equilibrium is a steady state,but it is dynamic in nature. What is the meaning of this statement?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo