(A) The total number of moles $n_{total} = n_A + n_B = 5 + 10 = 15 \ mol$. According to Dalton's Law of partial pressures,$P_i = x_i \times P_{total}$

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(A) The total number of moles $n_{total} = n_A + n_B = 5 + 10 = 15 \ mol$. According to Dalton's Law of partial pressures,$P_i = x_i \times P_{total}$,where $x_i$ is the mole fraction. $x_A = \frac{5}{15} = \frac{1}{3}$ and $x_B = \frac{10}{15} = \frac{2}{3}$. $P_A = x_A \times P_{total} = \frac{1}{3} \times 18 = 6 \ atm$. $P_B = x_B \times P_{total} = \frac{2}{3} \times 18 = 12 \ atm$.

Class 11 Chemistry States of Matter Characteristics and Measurable properties of gases

Medium

$A$ container contains $5 \ mol$ of $A$ and $10 \ mol$ of $B$. The total pressure of the container is $18 \ atm$. What are the partial pressures $P_A$ and $P_B$ respectively?

A
$6 \ atm, 12 \ atm$
B
$4 \ atm, 8 \ atm$
C
$3 \ atm, 9 \ atm$
D
$12 \ atm, 12 \ atm$

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Chemistry Questions

Chapter

States of Matter

Subtopic

Characteristics and Measurable properties of gases

At the same temperature and pressure,the rate of diffusion of gas $X$ is $3 \sqrt{3}$ times that of a gaseous hydrocarbon of molar mass $54 \ g \ mol^{-1}$. The molar mass of $X$ in $g \ mol^{-1}$ is

MediumAP EAMCET 2018

View Solution

Normal boiling point of water is $373 \ K$ (at $760 \ mm$). Vapour pressure of water at $298 \ K$ is $23 \ mm$. If the enthalpy of evaporation is $40.656 \ kJ/mole$,the boiling point of water at $23 \ mm$ pressure will be ............. $K$.

MediumAIPMT 1995

View Solution

Equal volume of $2$ gases $A$ and $B$ diffuse in $20 \ s$ and $10 \ s$ respectively. If molar mass of $A$ is $80$,then the molar mass of $B$ is:

Medium

View Solution

Equal amounts of two gases of molecular weights $4$ and $40$ are mixed. The pressure of the mixture is $1.1 \ atm$. What will be the partial pressure of the lighter gas in the mixture (in $atm$)?

MediumTS EAMCET 2020

View Solution

Which shape does a liquid have in its lowest energy state?

Easy

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

$A$ container contains $5 \ mol$ of $A$ and $10 \ mol$ of $B$. The total pressure of the container is $18 \ atm$. What are the partial pressures $P_A$ and $P_B$ respectively?

Similar Questions

At the same temperature and pressure,the rate of diffusion of gas $X$ is $3 \sqrt{3}$ times that of a gaseous hydrocarbon of molar mass $54 \ g \ mol^{-1}$. The molar mass of $X$ in $g \ mol^{-1}$ is

Normal boiling point of water is $373 \ K$ (at $760 \ mm$). Vapour pressure of water at $298 \ K$ is $23 \ mm$. If the enthalpy of evaporation is $40.656 \ kJ/mole$,the boiling point of water at $23 \ mm$ pressure will be ............. $K$.

Equal volume of $2$ gases $A$ and $B$ diffuse in $20 \ s$ and $10 \ s$ respectively. If molar mass of $A$ is $80$,then the molar mass of $B$ is:

Equal amounts of two gases of molecular weights $4$ and $40$ are mixed. The pressure of the mixture is $1.1 \ atm$. What will be the partial pressure of the lighter gas in the mixture (in $atm$)?

Which shape does a liquid have in its lowest energy state?

Vedclass Test Series

Exam Paper Generator

Online Exam Module