Equal amounts of two gases of molecular weights $4$ and $40$ are mixed. The pressure of the mixture is $1.1 \ atm$. What will be the partial pressure of the lighter gas in the mixture (in $atm$)?

  • A
    $0.25$
  • B
    $0.5$
  • C
    $0.8$
  • D
    $1$

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$A$ gaseous mixture of $3$ gases $A$, $B$ and $C$ has a pressure of $10 \,atm$. The total number of moles is $10$. If the partial pressures of gases $A$ and $B$ are $3 \,atm$ and $1 \,atm$ respectively, and the molar mass of gas $C$ is $2 \,g/mol$, calculate the weight of $C$ in the mixture. (in $\,g$)

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