Precipitation of CaF_2 (K_{sp} = 1.7 times 10 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) When equal volumes are mixed,the concentration of each ion is halved.For $CaF_2$,the ionic product $Q_{sp} = [Ca^{2+}][F^-]^2$.Precipitation occur

Vedclass · Accepted Answer

$10^{-2} \, M \, Ca^{2+} + 10^{-3} \, M \, F^{-}$

Vedclass · Answer

(B) When equal volumes are mixed,the concentration of each ion is halved.For $CaF_2$,the ionic product $Q_{sp} = [Ca^{2+}][F^-]^2$.Precipitation occurs if $Q_{sp} > K_{sp}$.For option $B$: $[Ca^{2+}] = \frac{10^{-2}}{2} = 5 	imes 10^{-3} \, M$ and $[F^-] = \frac{10^{-3}}{2} = 5 	imes 10^{-4} \, M$.$Q_{sp} = (5 	imes 10^{-3}) 	imes (5 	imes 10^{-4})^2 = 5 	imes 10^{-3} 	imes 25 	imes 10^{-8} = 1.25 	imes 10^{-9}$.Since $1.25 	imes 10^{-9} > 1.7 	imes 10^{-10}$,precipitation occurs.

Precipitation of $CaF_2$ $(K_{sp} = 1.7 \times 10^{-10})$ occurs when equal volumes of which of the following are mixed?

Similar Questions

Assign $A, B, C, D$ from the given type of reaction.
$CaCl_2 + Na_2C_2O_4 \longrightarrow CaC_2O_4\downarrow + 2NaCl$

At $298 \ K$ temperature,the $K_{sp}$ of $CaF_2$ is $1.7 \times 10^{-10}$. If a person drinks $2.5 \ L$ of $CaF_2$ saturated water daily,how many grams of $CaF_2$ are present in the water consumed? (Molecular mass of $CaF_2$ is $78 \ g \ mol^{-1}$)

The conductivity of a saturated solution of $BaSO_4$ is $3.06 \times 10^{-6} \ \Omega^{-1} \ cm^{-1}$ and its molar conductivity is $1.53 \ \Omega^{-1} \ cm^2 \ mol^{-1}$. What is the $K_{sp}$ of $BaSO_4$?

The $K_{sp}$ of $AgBr$ at $25 \, ^\circ C$ is $4.9 \times 10^{-13}$. If the molar mass of $AgBr$ is $188 \, g/mol$,how much $AgBr$ is required to saturate $20 \, L$ of water?

Which from the following equations represents the relation between solubility ($S$ in $mol \ L^{-1}$) and solubility product $(K_{sp})$ for a salt $B_3A_2$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module