The rate law for the reaction between substances $A$ and $B$ is given by $\text{Rate} = k[A]^n[B]^m$. If the concentration of $A$ is doubled and the concentration of $B$ is halved,what is the ratio of the new rate to the initial rate?
- A$2^{(n+m)}$
- B$\frac{1}{2^{(m-n)}}$
- C$2^{(n-m)}$
- D$2^{(m-n)}$
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