For the reaction $N_2 + 3H_2 \rightarrow 2NH_3$,if $\frac{d[NH_3]}{dt} = 2 \times 10^{-4} \ mol \ L^{-1} \ s^{-1}$,then what is the value of $-\frac{d[H_2]}{dt}$?
- A$6 \times 10^{-4} \ mol \ L^{-1} \ s^{-1}$
- B$1 \times 10^{-4} \ mol \ L^{-1} \ s^{-1}$
- C$3 \times 10^{-4} \ mol \ L^{-1} \ s^{-1}$
- D$4 \times 10^{-4} \ mol \ L^{-1} \ s^{-1}$
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