For the reaction frac{1}{2} A rightarrow 2B,t | vedclass

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Question

(B) For a general reaction $aA \rightarrow bB$,the rate of reaction is given by: Rate $= -\frac{1}{a} \frac{d[A]}{dt} = \frac{1}{b} \frac{d[B]}{dt}$.

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$-\frac{d[A]}{dt} = \frac{1}{4} \frac{d[B]}{dt}$

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(B) For a general reaction $aA \rightarrow bB$,the rate of reaction is given by: Rate $= -\frac{1}{a} \frac{d[A]}{dt} = \frac{1}{b} \frac{d[B]}{dt}$. Given the reaction $\frac{1}{2} A \rightarrow 2B$,here $a = \frac{1}{2}$ and $b = 2$. Substituting these values: Rate $= -\frac{1}{1/2} \frac{d[A]}{dt} = \frac{1}{2} \frac{d[B]}{dt}$. $-2 \frac{d[A]}{dt} = \frac{1}{2} \frac{d[B]}{dt}$. Multiplying both sides by $\frac{1}{2}$: $-\frac{d[A]}{dt} = \frac{1}{4} \frac{d[B]}{dt}$.

For the reaction $\frac{1}{2} A \rightarrow 2B$,the rate of disappearance of $A$ is related to the rate of appearance of $B$ by which of the following expressions?

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