For a zero-order reaction A rightarrow text{P | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) For a zero-order reaction,the half-life is given by $t_{1/2} = \frac{[A]_0}{2k}$.Given $t_{1/2} = 1 \ h$ and $[A]_0 = 2.0 \ mol \ L^{-1}$,we have

Vedclass · Accepted Answer

$0.25$

Vedclass · Answer

(D) For a zero-order reaction,the half-life is given by $t_{1/2} = \frac{[A]_0}{2k}$.Given $t_{1/2} = 1 \ h$ and $[A]_0 = 2.0 \ mol \ L^{-1}$,we have $1 = \frac{2.0}{2k}$,which gives the rate constant $k = 1.0 \ mol \ L^{-1} \ h^{-1}$.For a zero-order reaction,the rate law is $[A]_t = [A]_0 - kt$.To find the time $t$ for the concentration to change from $0.50 \ mol \ L^{-1}$ to $0.25 \ mol \ L^{-1}$,we use $\Delta [A] = k 	imes t$.$0.50 - 0.25 = 1.0 	imes t$.$0.25 = 1.0 	imes t$.Therefore,$t = 0.25 \ h$.

For a zero-order reaction $A \rightarrow \text{Product}$,the half-life is $1 \ h$. If the initial concentration of reactant $A$ is $2.0 \ mol \ L^{-1}$,how many hours will it take for the concentration to decrease from $0.50 \ mol \ L^{-1}$ to $0.25 \ mol \ L^{-1}$?

Similar Questions

The unit of the velocity constant in case of zero order reaction is

Mention True $(T)$ and False $(F)$ statements for the following expressions related to a zero-order reaction $R \to P$:
$I. \ k = \frac{[R]_0}{2 t_{1/2}}$
$II. \ t_{1/2} = \frac{[R]_0}{4k}$

In a zero-order reaction,if the initial concentration of the reactant is doubled,the time required for half the reactant to be consumed:

The unit of rate constant for a zero order reaction is

The formation of gas at the surface of tungsten due to adsorption is a reaction of which order?

Vedclass Test Series

Exam Paper Generator

Online Exam Module