(A) For a first-order reaction,the number of half-lives $(n)$ is calculated as $n = \frac{t}{t_{1/2}}$. Given $t = 96 \ \text{hours}$ and $t_{1/2} =

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(A) For a first-order reaction,the number of half-lives $(n)$ is calculated as $n = \frac{t}{t_{1/2}}$. Given $t = 96 \ \text{hours}$ and $t_{1/2} = 24 \ \text{hours}$,we have $n = \frac{96}{24} = 4$. The amount remaining after $n$ half-lives is given by the formula $N = N_0 \times (\frac{1}{2})^n$. Substituting the values,$N = 10 \ g \times (\frac{1}{2})^4 = 10 \times \frac{1}{16} = 0.625 \ g$. Thus,the amount of $N_2O_5$ remaining after $96 \ \text{hours}$ is $0.625 \ g$.

Class 12 Chemistry Chemical Kinetics First Order reaction

Easy

For the first-order reaction $N_2O_5 \to 2NO_2 + \frac{1}{2}O_2$,the half-life at $30 \ ^\circ C$ is $24 \ \text{hours}$. Starting with $10 \ g$ of $N_2O_5$,how many grams of $N_2O_5$ will remain after $96 \ \text{hours}$ (in $g$)?

A
$0.625$
B
$0.63$
C
$1.77$
D
$0.5$

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Class 12

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Chemical Kinetics

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First Order reaction

It takes $1 \, h$ for a first order reaction to go to $50 \, \%$ completion. The total time required for the same reaction to reach $87.5 \, \%$ completion will be $..... \, h$.

MediumKVPY 2016

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For a first-order reaction,if the value of $a/(a - x)$ is $8$ after $10 \text{ minutes}$,what will be the rate constant $K$?

Medium

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For the reaction $A \to B$,the rate law expression is: $\text{Rate} = k[A]$. Which of the following statements is incorrect?

Easy

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The rate constant of a first-order reaction is $1.20 \times 10^{-3} \, s^{-1}$. How much time will it take for $5 \, g$ of the reactant to reduce to $3 \, g$ (in $, s$)?

Medium

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At $298 \ K$,for a first order reaction $(A \rightarrow P)$ the following graph is obtained. The rate constant (in $s^{-1}$) and initial concentration (in $mol \ L^{-1}$) of '$A$' are respectively ($y$-axis $= \ln(a-x)$; $x$-axis $=$ time in sec).

MediumAP EAMCET 2013

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For the first-order reaction $N_2O_5 \to 2NO_2 + \frac{1}{2}O_2$,the half-life at $30 \ ^\circ C$ is $24 \ \text{hours}$. Starting with $10 \ g$ of $N_2O_5$,how many grams of $N_2O_5$ will remain after $96 \ \text{hours}$ (in $g$)?

Similar Questions

It takes $1 \, h$ for a first order reaction to go to $50 \, \%$ completion. The total time required for the same reaction to reach $87.5 \, \%$ completion will be $..... \, h$.

For a first-order reaction,if the value of $a/(a - x)$ is $8$ after $10 \text{ minutes}$,what will be the rate constant $K$?

For the reaction $A \to B$,the rate law expression is: $\text{Rate} = k[A]$. Which of the following statements is incorrect?

The rate constant of a first-order reaction is $1.20 \times 10^{-3} \, s^{-1}$. How much time will it take for $5 \, g$ of the reactant to reduce to $3 \, g$ (in $, s$)?

At $298 \ K$,for a first order reaction $(A \rightarrow P)$ the following graph is obtained. The rate constant (in $s^{-1}$) and initial concentration (in $mol \ L^{-1}$) of '$A$' are respectively ($y$-axis $= \ln(a-x)$; $x$-axis $=$ time in sec).

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