The total value of magnetic quantum number for $n = 4$ is:

Statement $A$: An orbital can accommodate a maximum of two electrons.
Reason $R$: Two electrons in an orbital produce opposite magnetic fields.

If the $n^{th}$ specific period of the periodic table contains $\frac{(n+2)^2}{2}$ elements,then the maximum value of the azimuthal quantum number associated with that period is:

Which two factors affect the energy of an electron in an orbit? How?

Arrange the $1s$,$2s$,$4s$,$2p$,$3p$,$4p$,and $3d$ orbitals according to increasing order of energy.

Degenerate atomic orbitals have