What is the decreasing order of energy for th | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The energy of an orbital in a multi-electron atom depends on the effective nuclear charge $(Z_{eff})$.As the atomic number $(Z)$ increases,the att

Vedclass · Accepted Answer

$E_{2s(H)} > E_{2s(Li)} > E_{2s(Na)} > E_{2s(K)}$

Vedclass · Answer

(A) The energy of an orbital in a multi-electron atom depends on the effective nuclear charge $(Z_{eff})$.As the atomic number $(Z)$ increases,the attraction between the nucleus and the electrons increases,which lowers the energy of the orbital.For the $2s$-orbital,the energy decreases as the nuclear charge increases.The atomic numbers are $H (Z=1)$,$Li (Z=3)$,$Na (Z=11)$,and $K (Z=19)$.Since $Z_{eff}$ increases from $H$ to $K$,the energy of the $2s$-orbital decreases in the order: $E_{2s(H)} > E_{2s(Li)} > E_{2s(Na)} > E_{2s(K)}$.

What is the decreasing order of energy for the $2s$-orbital of $H, Li, Na$,and $K$ atoms?

Similar Questions

The electronic configurations of four elements are given in brackets: $L\,(1s^2, 2s^2 2p^1)$; $M\,(1s^2, 2s^2 2p^5)$; $Q\,(1s^2, 2s^2 2p^6, 3s^1)$; $R\,(1s^2, 2s^2 2p^2)$. Which element would most readily form a diatomic molecule?

Which one of the following sets of quantum numbers is not possible for a $4p$ electron?

Which of the following is not a permissible arrangement of electrons in an atom?

When the value of azimuthal quantum number is $l = 3$,the magnetic quantum number $m_l$ can have values:

The number of $d$-electrons in $Fe^{2+}$ (atomic number of $Fe = 26$) is not equal to that of the

Vedclass Test Series

Exam Paper Generator

Online Exam Module