The increasing order of the rate of diffusion | vedclass

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Question

(C) According to Graham's Law of Diffusion,the rate of diffusion $(r)$ is inversely proportional to the square root of the molar mass $(M)$ of the gas

Vedclass · Accepted Answer

$CO_2 < O_2 < NH_3 < H_2$

Vedclass · Answer

(C) According to Graham's Law of Diffusion,the rate of diffusion $(r)$ is inversely proportional to the square root of the molar mass $(M)$ of the gas: $r \propto \frac{1}{\sqrt{M}}$.Calculating molar masses $(M)$:$M(H_2) = 2 \ g/mol$$M(NH_3) = 17 \ g/mol$$M(O_2) = 32 \ g/mol$$M(CO_2) = 44 \ g/mol$Since the rate of diffusion is inversely proportional to the square root of the molar mass,the order of increasing rate of diffusion is the order of decreasing molar mass: $CO_2 NH_3 > O_2 > CO_2$ (decreasing rate of diffusion).Therefore,the increasing order of the rate of diffusion is $CO_2 < O_2 < NH_3 < H_2$.

The increasing order of the rate of diffusion for the gases $H_2$,$O_2$,$NH_3$,and $CO_2$ is:

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