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(D) The root mean square speed $(v_{rms})$ of a gas is given by the formula: $v_{rms} = \sqrt{\frac{3RT}{M}}$.From this,we can see that $v_{rms} \prop

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twice the original

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(D) The root mean square speed $(v_{rms})$ of a gas is given by the formula: $v_{rms} = \sqrt{\frac{3RT}{M}}$.From this,we can see that $v_{rms} \propto \sqrt{T}$.Initial temperature $T_1 = 37 + 273 = 310 \, K$.Final temperature $T_2 = 927 + 273 = 1200 \, K$.Ratio of speeds: $\frac{v_{rms,2}}{v_{rms,1}} = \sqrt{\frac{T_2}{T_1}} = \sqrt{\frac{1200}{310}} \approx \sqrt{3.87} \approx 1.96 \approx 2$.Therefore,the speed becomes approximately twice the original speed.

If the temperature of a gas is increased from $37\,^oC$ to $927\,^oC$,then its original root mean square speed will become ...........

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