At STP,write the order of root mean square sp | vedclass

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(B) The root mean square speed $(u_{rms})$ of a gas is given by the formula: $u_{rms} = \sqrt{\frac{3RT}{M}}$.At a constant temperature $(T)$,$u_{rms}

Vedclass · Accepted Answer

$H_2 > N_2 > O_2 > HBr$

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(B) The root mean square speed $(u_{rms})$ of a gas is given by the formula: $u_{rms} = \sqrt{\frac{3RT}{M}}$.At a constant temperature $(T)$,$u_{rms} \propto \frac{1}{\sqrt{M}}$,where $M$ is the molar mass of the gas.The molar masses are: $H_2 = 2 \ g/mol$,$N_2 = 28 \ g/mol$,$O_2 = 32 \ g/mol$,and $HBr = 81 \ g/mol$.Since $u_{rms}$ is inversely proportional to the square root of the molar mass,the gas with the lowest molar mass will have the highest $u_{rms}$.The order of molar masses is: $H_2 Therefore,the order of $u_{rms}$ is: $H_2 > N_2 > O_2 > HBr$.

At $STP$,write the order of root mean square speed $(u_{rms})$ for the molecules $H_2, N_2, O_2$,and $HBr$.

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