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(B) According to Charles's Law,at constant pressure,the volume of a fixed mass of gas is directly proportional to its absolute temperature: $V \propto

Vedclass · Accepted Answer

$273$

Vedclass · Answer

(B) According to Charles's Law,at constant pressure,the volume of a fixed mass of gas is directly proportional to its absolute temperature: $V \propto T$ or $\frac{V_1}{T_1} = \frac{V_2}{T_2}$.Given: $V_1 = 2 \ L$,$T_1 = 273 \ K$ (at $STP$),$V_2 = 4 \ L$.Substituting the values: $\frac{2}{273} = \frac{4}{T_2}$.$T_2 = \frac{4 	imes 273}{2} = 546 \ K$.To convert the temperature to Celsius: $T(^\circ C) = T(K) - 273$.$T(^\circ C) = 546 - 273 = 273 \ ^\circ C$.

$A$ certain mass of gas occupies a volume of $2 \ L$ at $STP$. If the pressure is kept constant,what will be the temperature in $^\circ C$ for the gas to occupy a volume of $4 \ L$?

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