For gases W, X, Y and Z,the van der Waals con | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The critical temperature $(T_c)$ is given by the formula: $T_c = \frac{8a}{27Rb}$.Since $T_c \propto \frac{a}{b}$,we calculate the ratio $\frac{a}

Vedclass · Accepted Answer

$Z$

Vedclass · Answer

(D) The critical temperature $(T_c)$ is given by the formula: $T_c = \frac{8a}{27Rb}$.Since $T_c \propto \frac{a}{b}$,we calculate the ratio $\frac{a}{b}$ for each gas:For $W$: $\frac{4.0}{0.027} \approx 148.15$For $X$: $\frac{8.0}{0.030} \approx 266.67$For $Y$: $\frac{6.0}{0.032} = 187.5$For $Z$: $\frac{12.0}{0.027} \approx 444.44$Since gas $Z$ has the highest ratio of $\frac{a}{b}$,it has the highest critical temperature.

Gas	$a$ (atm $L^2$ mol$^{-2}$)	$b$ ($L$ mol$^{-1}$)
$W$	$4.0$	$0.027$
$X$	$8.0$	$0.030$
$Y$	$6.0$	$0.032$
$Z$	$12.0$	$0.027$

For gases $W, X, Y$ and $Z$,the van der Waals constants are given below. Which gas has the highest critical temperature?
Gas $a$ (atm $L^2$ mol$^{-2}$) $b$ ($L$ mol$^{-1}$)
$W$ $4.0$ $0.027$
$X$ $8.0$ $0.030$
$Y$ $6.0$ $0.032$
$Z$ $12.0$ $0.027$

Similar Questions

Amongst the following statements,the correct one is

Liquefaction of a gas can occur $....................$

Four gas cylinders containing $He$,$N_2$,$CO_2$ and $NH_3$ gases separately are gradually cooled from a temperature of $500 \ K$. Which gas will liquefy first?
(Given $T_C$ in $K - He: 5.3, N_2: 126, CO_2: 304.1$ and $NH_3: 405.5$)

What happens when $CO_2$ is compressed and expanded at a constant temperature of $30.98 \, ^\circ C$?

Explain the liquefaction of real gases and permanent gases.

Vedclass Test Series

Exam Paper Generator

Online Exam Module

For gases $W, X, Y$ and $Z$,the van der Waals constants are given below. Which gas has the highest critical temperature?Gas$a$ (atm $L^2$ mol$^{-2}$)$b$ ($L$ mol$^{-1}$)$W$$4.0$$0.027$$X$$8.0$$0.030$$Y$$6.0$$0.032$$Z$$12.0$$0.027$