Four gas cylinders containing He,N_2,CO_2 and | vedclass

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(D) The ease of liquefaction of a gas is directly proportional to its critical temperature $(T_C)$.As the temperature is lowered from $500 \ K$,the ga

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$NH_3$

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(D) The ease of liquefaction of a gas is directly proportional to its critical temperature $(T_C)$.As the temperature is lowered from $500 \ K$,the gas with the highest critical temperature will reach its liquefaction point first.Comparing the given critical temperatures: $NH_3$ $(405.5 \ K)$ > $CO_2$ $(304.1 \ K)$ > $N_2$ $(126 \ K)$ > $He$ $(5.3 \ K)$.Since $NH_3$ has the highest critical temperature,it will liquefy first.

Four gas cylinders containing $He$,$N_2$,$CO_2$ and $NH_3$ gases separately are gradually cooled from a temperature of $500 \ K$. Which gas will liquefy first?
(Given $T_C$ in $K - He: 5.3, N_2: 126, CO_2: 304.1$ and $NH_3: 405.5$)

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Four gas cylinders containing $He$,$N_2$,$CO_2$ and $NH_3$ gases separately are gradually cooled from a temperature of $500 \ K$. Which gas will liquefy first?(Given $T_C$ in $K - He: 5.3, N_2: 126, CO_2: 304.1$ and $NH_3: 405.5$)