If the temperature increases from 20,^oC to 4 | vedclass

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Question

(C) The average kinetic energy $(KE_{avg})$ of an ideal gas is directly proportional to its absolute temperature $(T)$ in Kelvin.$KE_{avg} = \frac{3}{

Vedclass · Accepted Answer

$313/293$

Vedclass · Answer

(C) The average kinetic energy $(KE_{avg})$ of an ideal gas is directly proportional to its absolute temperature $(T)$ in Kelvin.$KE_{avg} = \frac{3}{2} k_B T$Initial temperature $T_1 = 20 + 273 = 293\,K$.Final temperature $T_2 = 40 + 273 = 313\,K$.The ratio of average kinetic energy is $\frac{KE_2}{KE_1} = \frac{T_2}{T_1} = \frac{313}{293}$.Therefore,the factor by which the average kinetic energy changes is $313/293$.

If the temperature increases from $20\,^oC$ to $40\,^oC$,by what factor does the average kinetic energy of neon atoms change?

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