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(D) According to Graham's Law of Diffusion,the rate of diffusion $(r)$ of a gas is inversely proportional to the square root of its molar mass $(M)$:

Vedclass · Accepted Answer

$4 : 1$

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(D) According to Graham's Law of Diffusion,the rate of diffusion $(r)$ of a gas is inversely proportional to the square root of its molar mass $(M)$: $r \propto \frac{1}{\sqrt{M}}$.For an equimolar mixture,the ratio of the rates of diffusion of $H_2$ and $O_2$ is given by: $\frac{r_{H_2}}{r_{O_2}} = \sqrt{\frac{M_{O_2}}{M_{H_2}}}$.The molar mass of $H_2$ $(M_{H_2})$ is $2 \ g/mol$ and the molar mass of $O_2$ $(M_{O_2})$ is $32 \ g/mol$.Substituting these values: $\frac{r_{H_2}}{r_{O_2}} = \sqrt{\frac{32}{2}} = \sqrt{16} = 4$.Therefore,the ratio is $4 : 1$.

$A$ football bladder contains an equimolar mixture of $H_2$ and $O_2$. What is the ratio of the rate of diffusion of $H_2$ to $O_2$?

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