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(D) Mass of chlorophyll = $2.00 \ g$. Percentage of $Mg$ in chlorophyll = $2.68\%$. Mass of $Mg$ in $2.00 \ g$ of chlorophyll = $\frac{2.68}{100} 	im

Vedclass · Accepted Answer

$1.345 	imes 10^{23}$

Vedclass · Answer

(D) Mass of chlorophyll = $2.00 \ g$. Percentage of $Mg$ in chlorophyll = $2.68\%$. Mass of $Mg$ in $2.00 \ g$ of chlorophyll = $\frac{2.68}{100} 	imes 2.00 = 0.0536 \ g$. Molar mass of $Mg = 24 \ g/mol$. Number of moles of $Mg = \frac{	ext{Mass}}{	ext{Molar mass}} = \frac{0.0536}{24} \approx 0.002233 \ mol$. Number of $Mg$ atoms = $	ext{Moles} 	imes N_A = 0.002233 	imes 6.022 	imes 10^{23} \approx 1.345 	imes 10^{21}$ atoms. Wait,re-calculating: $0.0536 / 24 = 0.0022333$. $0.0022333 	imes 6.022 	imes 10^{23} = 1.345 	imes 10^{21}$. Correction: The provided option $D$ is $1.345 	imes 10^{23}$,which implies a calculation error in the source material or a typo in the question's mass/percentage. Based on standard stoichiometry,the result is $1.345 	imes 10^{21}$. Given the options,$D$ is the intended answer assuming a factor of $100$ difference.

Chlorophyll,the green pigment in plants responsible for photosynthesis,contains $2.68\%$ of magnesium by mass. Calculate the number of magnesium atoms in $2.00 \ g$ of chlorophyll.

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