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(A) $1$. Calculate the moles of each element by dividing the mass ratio by their respective atomic masses: $C = 9/12 = 0.75$,$H = 1/1 = 1$,$N = 3.5/14

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$C_6H_8N_2$

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(A) $1$. Calculate the moles of each element by dividing the mass ratio by their respective atomic masses: $C = 9/12 = 0.75$,$H = 1/1 = 1$,$N = 3.5/14 = 0.25$. $2$. Determine the simplest molar ratio by dividing by the smallest value $(0.25)$: $C = 0.75/0.25 = 3$,$H = 1/0.25 = 4$,$N = 0.25/0.25 = 1$. $3$. The empirical formula is $C_3H_4N$. $4$. Calculate the empirical formula mass: $(3 	imes 12) + (4 	imes 1) + (1 	imes 14) = 36 + 4 + 14 = 54 \ g \ mol^{-1}$. $5$. Calculate the factor $n = 	ext{Molecular mass} / 	ext{Empirical formula mass} = 108 / 54 = 2$. $6$. The molecular formula is $n 	imes (C_3H_4N) = C_6H_8N_2$.

The molecular mass of an organic compound is $108 \ g \ mol^{-1}$. If $C, H,$ and $N$ atoms are present in the weight ratio of $9 : 1 : 3.5$,what is the molecular formula?

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