What is the weight of 1 times 10^{22} molecul | vedclass

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(B) The molar mass of $CuSO_4 \cdot 5H_2O$ is calculated as: $63.5 + 32 + (4 	imes 16) + 5 	imes (2 + 16) = 63.5 + 32 + 64 + 90 = 249.5 	ext{ g/mol

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$4.143$

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(B) The molar mass of $CuSO_4 \cdot 5H_2O$ is calculated as: $63.5 + 32 + (4 	imes 16) + 5 	imes (2 + 16) = 63.5 + 32 + 64 + 90 = 249.5 	ext{ g/mol}$.We know that $6.022 	imes 10^{23}$ molecules of $CuSO_4 \cdot 5H_2O$ weigh $249.5 	ext{ g}$.Therefore,the weight of $1 	imes 10^{22}$ molecules is given by:$	ext{Weight} = \frac{249.5 	ext{ g}}{6.022 	imes 10^{23} 	ext{ molecules}} 	imes 1 	imes 10^{22} 	ext{ molecules}$.$	ext{Weight} = \frac{249.5}{6.022} 	imes 10^{-1} 	ext{ g} \approx 41.43 	imes 0.1 	ext{ g} = 4.143 	ext{ g}$.

What is the weight of $1 \times 10^{22}$ molecules of $CuSO_4 \cdot 5H_2O$ in grams?

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