How many moles of Mg_3(PO_4)_2 contain 0.25 m | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The chemical formula of magnesium phosphate is $Mg_3(PO_4)_2$.One mole of $Mg_3(PO_4)_2$ contains $4 	imes 2 = 8$ moles of oxygen atoms.Therefore

Vedclass · Accepted Answer

$3.125 	imes 10^{-2}$

Vedclass · Answer

(A) The chemical formula of magnesium phosphate is $Mg_3(PO_4)_2$.One mole of $Mg_3(PO_4)_2$ contains $4 	imes 2 = 8$ moles of oxygen atoms.Therefore,$8$ moles of oxygen atoms are present in $1$ mole of $Mg_3(PO_4)_2$.To find the moles of $Mg_3(PO_4)_2$ containing $0.25$ moles of oxygen atoms:$	ext{Moles of } Mg_3(PO_4)_2 = \frac{0.25}{8} = 0.03125 = 3.125 	imes 10^{-2}$ moles.

How many moles of $Mg_3(PO_4)_2$ contain $0.25$ moles of oxygen atoms?

Similar Questions

The maximum number of molecules is present in

The number of oxygen atoms in $4.4 \ g$ of $CO_2$ is approximately:

The total number of electrons present in $18 \ mL$ water (density $= 1 \ g/mL$) is

If a gaseous mixture contains $20\%$ $H_2$ by weight,what is the number of moles of $H_2$ in $100 \ g$ of the mixture (in $mol$)?

The mass of a sample of aluminum is $54 \ g$. The mass of the same number of magnesium atoms will be ......... $g$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module