5.06 g of pure cupric oxide (CuO) on complet | vedclass

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(B) Experiment $I$: Mass of $CuO = 5.06 \ g$,Mass of $Cu = 4.04 \ g$. Mass of $O = 5.06 - 4.04 = 1.02 \ g$. Ratio of $Cu : O = 4.04 / 1.02 \approx 3.9

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Law of Definite Proportions

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(B) Experiment $I$: Mass of $CuO = 5.06 \ g$,Mass of $Cu = 4.04 \ g$. Mass of $O = 5.06 - 4.04 = 1.02 \ g$. Ratio of $Cu : O = 4.04 / 1.02 \approx 3.96 : 1$. Experiment $II$: Mass of $Cu = 1.3 \ g$,Mass of $CuO = 1.63 \ g$. Mass of $O = 1.63 - 1.3 = 0.33 \ g$. Ratio of $Cu : O = 1.3 / 0.33 \approx 3.94 : 1$. Since the ratio of the masses of elements in the compound is the same in both experiments,it illustrates the Law of Definite Proportions.

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