The number of oxygen atoms in 4.4 g of CO_2 | vedclass

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Question

(A) The molar mass of $CO_2$ is $12 + (2 	imes 16) = 44 \ g/mol$. Moles of $CO_2 = \frac{	ext{given mass}}{	ext{molar mass}} = \frac{4.4 \ g}{44 \

Vedclass · Accepted Answer

$1.2 	imes 10^{23}$

Vedclass · Answer

(A) The molar mass of $CO_2$ is $12 + (2 	imes 16) = 44 \ g/mol$. Moles of $CO_2 = \frac{	ext{given mass}}{	ext{molar mass}} = \frac{4.4 \ g}{44 \ g/mol} = 0.1 \ mol$. Number of molecules of $CO_2 = 	ext{moles} 	imes N_A = 0.1 	imes 6.022 	imes 10^{23} = 6.022 	imes 10^{22}$ molecules. Since $1$ molecule of $CO_2$ contains $2$ oxygen atoms,the number of oxygen atoms $= 2 	imes (6.022 	imes 10^{22}) = 12.044 	imes 10^{22} = 1.2044 	imes 10^{23}$ atoms. Thus,the number of oxygen atoms is approximately $1.2 	imes 10^{23}$.

The number of oxygen atoms in $4.4 \ g$ of $CO_2$ is approximately:

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