A substance contains 52.2% carbon,13% hydroge | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) ElementPercentageAtomic WeightRatio (\%/At. Wt.)Simple Ratio$C$$52.2$$12$$52.2/12 = 4.35$$4.35/2.175 = 2$$H$$13$$1$$13/1 = 13$$13/2.175 = 6$$O$$34

Vedclass · Accepted Answer

$C_4H_{12}O_2$

Vedclass · Answer

(C) ElementPercentageAtomic WeightRatio (\%/At. Wt.)Simple Ratio$C$$52.2$$12$$52.2/12 = 4.35$$4.35/2.175 = 2$$H$$13$$1$$13/1 = 13$$13/2.175 = 6$$O$$34.8$$16$$34.8/16 = 2.175$$2.175/2.175 = 1$The empirical formula is $C_2H_6O$.Empirical formula mass $= (2 	imes 12) + (6 	imes 1) + 16 = 24 + 6 + 16 = 46$.Molecular mass $= 2 	imes 	ext{Vapor Density} = 2 	imes 46 = 92$.$n = \frac{	ext{Molecular mass}}{	ext{Empirical formula mass}} = \frac{92}{46} = 2$.Molecular formula $= n 	imes (	ext{Empirical formula}) = 2 	imes C_2H_6O = C_4H_{12}O_2$.

$A$ substance contains $52.2\%$ carbon,$13\%$ hydrogen,and $34.8\%$ oxygen. If the vapor density of the substance is $46$,find its molecular formula.

Similar Questions

An organic substance $(80 \ g)$ on analysis was found to contain $C = 24 \ g$,$H = 4 \ g$,and $O = 32 \ g$. What is its empirical formula?

If the fertilizers listed below are priced according to their nitrogen content,which will be the least expensive per $50 \ kg$ bag?

In which of the following pairs of compounds is the ratio of $C$,$H$,and $O$ the same?

$0.48 \ g$ of an organic compound on complete combustion produced $0.22 \ g$ of $CO_2$. The percentage of $C$ in the given organic compound is

Analysis of an organic compound shows $C = 40\%$,$H = 13.33\%$,and $N = 46.67\%$. Its empirical formula is ....

Vedclass Test Series

Exam Paper Generator

Online Exam Module