If m_1 g of metal A displaces m_2 g of anot | vedclass

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(A) According to the law of equivalence,when one metal displaces another from its salt solution,the number of equivalents of the two metals must be eq

Vedclass · Accepted Answer

$\frac{m_1}{m_2} 	imes E_2$

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(A) According to the law of equivalence,when one metal displaces another from its salt solution,the number of equivalents of the two metals must be equal.Number of equivalents of metal $A$ = Number of equivalents of metal $B$.Since,$	ext{Number of equivalents} = \frac{	ext{mass}}{	ext{equivalent weight}}$,we have:$\frac{m_1}{E_1} = \frac{m_2}{E_2}$.Rearranging the equation to find $E_1$ (equivalent weight of $A$):$E_1 = \frac{m_1}{m_2} 	imes E_2$.

If $m_1 \ g$ of metal $A$ displaces $m_2 \ g$ of another metal $B$ from its salt solution,and their equivalent weights are $E_1$ and $E_2$ respectively,how is the equivalent weight of $A$ expressed?

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