$2 \ g$ of metal carbonate is neutralized completely by $100 \ mL$ of $0.1 \ N$ $HCl$. The equivalent weight of metal carbonate is:

An appropriate method for molecular weight determination of chloroform $(CHCl_3)$ is:

$A$ metal oxide is reduced by heating it in a stream of hydrogen. It is found that after complete reduction,$3.15 \, g$ of the oxide yielded $1.05 \, g$ of the metal. We may deduce that:

In chlorine gas,the ratio of $Cl^{35}$ and $Cl^{37}$ is

Atoms consist of protons,neutrons,and electrons. If the mass of neutrons were made half and the mass of electrons were made two times their actual masses,then the atomic mass of $_6C^{12}$ would:

$1 \ amu$ is equal to