When 100 , g of CaCO_3 reacts with 1 , N , HC | vedclass

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(C) The balanced chemical equation is: $CaCO_3 + 2HCl 	o CaCl_2 + CO_2 + H_2O$. From the stoichiometry,$1 \, mol$ of $CaCO_3$ $(100 \, g)$ reacts wit

Vedclass · Accepted Answer

$22$

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(C) The balanced chemical equation is: $CaCO_3 + 2HCl 	o CaCl_2 + CO_2 + H_2O$. From the stoichiometry,$1 \, mol$ of $CaCO_3$ $(100 \, g)$ reacts with $2 \, mol$ of $HCl$ to produce $1 \, mol$ of $CO_2$ $(44 \, g)$. Since the reaction uses $1 \, N \, HCl$ (which is $1 \, M \, HCl$ for this acid),only $1 \, mol$ of $HCl$ is available per liter. Therefore,$100 \, g$ of $CaCO_3$ $(1 \, mol)$ will react with $1 \, mol$ of $HCl$ to produce $0.5 \, mol$ of $CO_2$. Mass of $CO_2 = 0.5 \, mol 	imes 44 \, g/mol = 22 \, g$.

When $100 \, g$ of $CaCO_3$ reacts with $1 \, N \, HCl$,how many grams of $CO_2$ will be obtained upon completion of the reaction?

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