The normality of orthophosphoric acid having | vedclass

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(A) $1$. Given: Purity = $70\%$ by weight,Specific gravity $(d)$ = $1.54 \ g/mL$.$2$. Assume $100 \ g$ of the solution. The mass of $H_3PO_4$ is $70 \

Vedclass · Accepted Answer

$11$

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(A) $1$. Given: Purity = $70\%$ by weight,Specific gravity $(d)$ = $1.54 \ g/mL$.$2$. Assume $100 \ g$ of the solution. The mass of $H_3PO_4$ is $70 \ g$.$3$. Volume of the solution $(V)$ = $\frac{	ext{Mass}}{	ext{Density}} = \frac{100 \ g}{1.54 \ g/mL} = 64.935 \ mL$.$4$. Equivalent mass of $H_3PO_4$ (tribasic acid) = $\frac{	ext{Molar mass}}{3} = \frac{98}{3} = 32.67 \ g/eq$.$5$. Normality $(N)$ = $\frac{	ext{Mass of solute}}{	ext{Equivalent mass} 	imes V(L)} = \frac{70}{32.67 	imes (64.935 / 1000)} \approx 11 \ N$.

The normality of orthophosphoric acid having purity of $70\%$ by weight and specific gravity $1.54$ would be ............. $N$.

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