The number of atoms in $558.5 \ g$ of $Fe$ is equal to: [Atomic mass of $Fe = 55.85 \ g/mol$]
- A$558.5 \times 6.022 \times 10^{23}$
- BTwice the number of atoms in $60 \ g$ of $Carbon$
- CHalf the number of atoms in $8 \ g$ of $He$
- D$6.02 \times 10^{22}$
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