The number of molecules and atoms present in | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The molar mass of chlorine gas $(Cl_2)$ is $71 \ g/mol$.The number of moles of $Cl_2$ in $7.1 \ g$ is $\frac{7.1}{71} = 0.1 \ mol$.Number of molec

Vedclass · Accepted Answer

$\frac{N_A}{10} 	ext{ molecules}, \frac{N_A}{5} 	ext{ atoms}$

Vedclass · Answer

(B) The molar mass of chlorine gas $(Cl_2)$ is $71 \ g/mol$.The number of moles of $Cl_2$ in $7.1 \ g$ is $\frac{7.1}{71} = 0.1 \ mol$.Number of molecules = $	ext{moles} 	imes N_A = 0.1 	imes N_A = \frac{N_A}{10} 	ext{ molecules}$.Since each $Cl_2$ molecule contains $2$ atoms of chlorine,the number of atoms = $2 	imes 	ext{number of molecules} = 2 	imes \frac{N_A}{10} = \frac{N_A}{5} 	ext{ atoms}$.

The number of molecules and atoms present in $7.1 \ g$ of chlorine gas $(Cl_2)$ are respectively:

Similar Questions

What is the symbol for the $SI$ unit of mole? How is the mole defined?

The system that contains the maximum number of atoms is

At the same temperature,$10 \ dm^3$ of $N_2$ gas and $10 \ dm^3$ of gas $x$ contain the same number of molecules. What is the gas $x$?

What is the number of $CO_2$ molecules in $45.42 \ L$ at $\text{STP}$? (Consider molar volume of gas at $\text{STP} = 22.71 \ L \ mol^{-1}$)

The largest number of molecules are in:

Vedclass Test Series

Exam Paper Generator

Online Exam Module