A cylinder rolls up an inclined plane to a ce | vedclass

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(D) When the cylinder rolls up the incline,it has a tendency to slide down due to gravity,but the rotation causes it to move up. The friction acts in

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Upwards while ascending and upwards while descending

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(D) When the cylinder rolls up the incline,it has a tendency to slide down due to gravity,but the rotation causes it to move up. The friction acts in the direction that opposes the tendency to slide,which is upwards along the incline to provide the necessary torque for rolling.When the cylinder rolls down the incline,it has a tendency to slide down. The friction acts upwards along the incline to oppose this sliding tendency and provide the necessary torque for rolling.Therefore,in both cases (ascending and descending),the frictional force acts upwards along the inclined plane.

Column-$I$	Column-$II$
$(A)$ Ring	$(I)$ $\frac{Mg \sin \theta}{3.5}$
$(B)$ Solid sphere	$(II)$ $\frac{Mg \sin \theta}{2}$
$(C)$ Solid cylinder	$(III)$ $\frac{Mg \sin \theta}{3}$
$(D)$ Hollow cylinder	$(IV)$ $\frac{Mg \sin \theta}{2.5}$

$A$ cylinder rolls up an inclined plane to a certain height and then rolls down. (It does not slip during the entire motion.) What is the direction of the frictional force acting on the cylinder?

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