For a cube of side $a$ and mass $M$,the moment of inertia is minimum about which axis?

Three point masses $m_1, m_2, m_3$ are located at the vertices of an equilateral triangle of side length $a$. The moment of inertia of the system about an axis along the altitude of the triangle passing through $m_1$ is:

The radius of gyration of a uniform thin rod of length $L$ about an axis passing normally through its centre of mass is:

$Assertion$ : Moment of inertia depends on the axis of rotation and the nature of distribution of the mass of the body.
$Reason$ : Moment of inertia is the rotational inertia of the body.

Two rings have their masses in ratio $1 : 2$ and their diameters are in the ratio $2 : 1$. The ratio of their moments of inertia is

Moment of Inertia $(M.I.)$ of four bodies having same mass $M$ and radius $2R$ are as follows:
$I_{1} =$ $M.I.$ of solid sphere about its diameter
$I_{2} =$ $M.I.$ of solid cylinder about its axis
$I_{3} =$ $M.I.$ of solid circular disc about its diameter
$I_{4} =$ $M.I.$ of thin circular ring about its diameter
If $2(I_{2} + I_{3}) + I_{4} = x I_{1}$,then the value of $x$ will be...