The sequence of a processed m-RNA is given as | vedclass

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(B) $1$. The given $m-RNA$ sequence is $5'-AUG\ CUA\ UAC\ CUC\ CUU\ UAU\ CUG\ UGA-3'$.$2$. The translation process begins at the start codon $AUG$,whi

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$7$

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(B) $1$. The given $m-RNA$ sequence is $5'-AUG\ CUA\ UAC\ CUC\ CUU\ UAU\ CUG\ UGA-3'$.$2$. The translation process begins at the start codon $AUG$,which codes for Methionine.$3$. The codons are read in triplets: $AUG$ (Met),$CUA$ (Leu),$UAC$ (Tyr),$CUC$ (Leu),$CUU$ (Leu),$UAU$ (Tyr),$CUG$ (Leu).$4$. The sequence $UGA$ is a stop codon (nonsense codon) and does not code for any amino acid.$5$. Counting the codons before the stop codon: $AUG, CUA, UAC, CUC, CUU, UAU, CUG$ equals $7$ codons.$6$. Therefore,the polypeptide chain will consist of $7$ amino acids.

List-$I$	List-$II$
$(p)$ $UUU$	$(1)$ $Pro$
$(q)$ $AAA$	$(2)$ $Gly$
$(r)$ $CCC$	$(3)$ $Phe$
$(s)$ $GGG$	$(4)$ $Lys$

The sequence of a processed $m-RNA$ is given as $5'-AUG\ CUA\ UAC\ CUC\ CUU\ UAU\ CUG\ UGA-3'$. How many amino acids will be present in the polypeptide chain translated from this $m-RNA$?

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Codon on $mRNA$ and anticodon on $tRNA$ are

The initiation codon is ...... .

$A$: Triplet genetic code can be confirmed by frame shift mutations.
$R$: Frame shifting involves the change in protein product coded by triplet codons.

$A$ polypeptide is produced as dictated by $mRNA$. The number of bases on the $mRNA$ that code for the polypeptide portion containing the $N$-terminal amino acid and the next $13$ amino acids is:

Match List-$I$ with List-$II$ and select the correct option:
List-$I$ List-$II$
$(p)$ $UUU$ $(1)$ $Pro$
$(q)$ $AAA$ $(2)$ $Gly$
$(r)$ $CCC$ $(3)$ $Phe$
$(s)$ $GGG$ $(4)$ $Lys$

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