A polypeptide is produced as dictated by mRNA | vedclass

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(C) The genetic code is a triplet,meaning $3$ nitrogenous bases code for $1$ amino acid.To code for the $N$-terminal amino acid (which is the $1$st am

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$42$

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(C) The genetic code is a triplet,meaning $3$ nitrogenous bases code for $1$ amino acid.To code for the $N$-terminal amino acid (which is the $1$st amino acid) and the next $13$ amino acids,we need to code for a total of $1 + 13 = 14$ amino acids.Since each amino acid requires $3$ bases,the total number of bases required is $14 	imes 3 = 42$ bases.Therefore,the correct option is $42$.

$A$ polypeptide is produced as dictated by $mRNA$. The number of bases on the $mRNA$ that code for the polypeptide portion containing the $N$-terminal amino acid and the next $13$ amino acids is:

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