$A$ polypeptide is produced as dictated by $mRNA$. The number of bases on the $mRNA$ that code for the polypeptide portion containing the $N$-terminal amino acid and the next $13$ amino acids is:
- A$26$
- B$36$
- C$42$
- D$39$
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Similar Questions
If an $RNA$ sequence has $999$ bases and codes for a protein with $333$ amino acids,and the base at position $901$ is deleted,resulting in a sequence of $998$ bases,how many codons will be altered?
Difficult
View SolutionChoose the correct pair.
Column-$I$ Column-$II$ $A$. $AUG$ $1$. Phenylalanine $B$. $UAA$ $2$. Methionine $C$. $UUU$ $3$. Tryptophan $D$. $UGG$ $4$. Stop
| Column-$I$ | Column-$II$ |
|---|---|
| $A$. $AUG$ | $1$. Phenylalanine |
| $B$. $UAA$ | $2$. Methionine |
| $C$. $UUU$ | $3$. Tryptophan |
| $D$. $UGG$ | $4$. Stop |
Medium
View SolutionWhen more than one codon codes for the same amino acid,this is called as
Medium
View SolutionThere is only one possible sequence of amino acids when deduced from a given nucleotide sequence. However,multiple nucleotide sequences can be deduced from a single amino acid sequence. Explain this phenomenon.
Medium
View SolutionIf the genetic code were a tetraplet (four-letter code),how many possible codons would exist for $20$ types of amino acids?
Medium
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