70 , cal of heat are required to raise the te | vedclass

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(B) Given: $\mu = 2 \, moles$,$(\Delta Q)_P = 70 \, cal$,$\Delta T = 35^{\circ}C - 30^{\circ}C = 5 \, K$,$R = 2 \, cal/mol \cdot K$.At constant pressu

Vedclass · Accepted Answer

$50$

Vedclass · Answer

(B) Given: $\mu = 2 \, moles$,$(\Delta Q)_P = 70 \, cal$,$\Delta T = 35^{\circ}C - 30^{\circ}C = 5 \, K$,$R = 2 \, cal/mol \cdot K$.At constant pressure,the heat supplied is given by $(\Delta Q)_P = \mu C_P \Delta T$.Substituting the values: $70 = 2 	imes C_P 	imes 5$.$70 = 10 	imes C_P$,which gives $C_P = 7 \, cal/mol \cdot K$.Using the Mayer's relation: $C_P - C_V = R$.$C_V = C_P - R = 7 - 2 = 5 \, cal/mol \cdot K$.Now,at constant volume,the heat required is $(\Delta Q)_V = \mu C_V \Delta T$.$(\Delta Q)_V = 2 	imes 5 	imes 5 = 50 \, cal$.

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