C_6H_6 + X xrightarrow{anhydrous AlCl_3} text | vedclass

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Question

(C) The reaction sequence is the industrial cumene process for the preparation of phenol.Step $1$: Benzene $(C_6H_6)$ reacts with isopropyl chloride $

Vedclass · Accepted Answer

$CH_3CH(Cl)CH_3, C_6H_5OH, CH_3COCH_3$

Vedclass · Answer

(C) The reaction sequence is the industrial cumene process for the preparation of phenol.Step $1$: Benzene $(C_6H_6)$ reacts with isopropyl chloride $(CH_3CH(Cl)CH_3)$ in the presence of anhydrous $AlCl_3$ (Friedel-Crafts alkylation) to form isopropylbenzene (cumene).Step $2$: Cumene is oxidized by $O_2$ to form cumene hydroperoxide,which upon acid hydrolysis $(H^+)$ yields phenol $(C_6H_5OH)$ as $Y$ and acetone $(CH_3COCH_3)$ as $Z$.Therefore,$X = CH_3CH(Cl)CH_3$,$Y = C_6H_5OH$,and $Z = CH_3COCH_3$.

$C_6H_6 + X \xrightarrow{anhydrous AlCl_3} \text{Isopropylbenzene} \xrightarrow{(i) O_2, (ii) H^+} Y + Z$. In this reaction,$X, Y$ and $Z$ are . . . . . . respectively.

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