mathop {lim }limits_{x to infty } frac{{log { | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) આપણને લક્ષ $\mathop {\lim }\limits_{x 	o \infty } \frac{{\log {x^n} - [x]}}{{[x]}}$ આપેલ છે.આને $\mathop {\lim }\limits_{x 	o \infty } \left( \f

Vedclass · Accepted Answer

કિંમત $-1$ છે

Vedclass · Answer

(A) આપણને લક્ષ $\mathop {\lim }\limits_{x 	o \infty } \frac{{\log {x^n} - [x]}}{{[x]}}$ આપેલ છે.આને $\mathop {\lim }\limits_{x 	o \infty } \left( \frac{{\log {x^n}}}{{[x]}} - \frac{{[x]}}{{[x]}} ight)$ તરીકે લખી શકાય.જેમ $x 	o \infty,$ $[x] \approx x$ થાય.તેથી,$\mathop {\lim }\limits_{x 	o \infty } \frac{{\log {x^n}}}{{[x]}} = \mathop {\lim }\limits_{x 	o \infty } \frac{{n \log x}}{x} = 0.$આમ,અંતિમ જવાબ $0 - 1 = -1$ મળે છે.

Similar Questions

$\lim\limits_{x \rightarrow 0} \frac{\int\limits_{0}^{x} t \sin (10 t) d t}{x}$ ની કિંમત શોધો.

લક્ષ $\mathop {\lim }\limits_{x \to 0} \frac{{{e^x} - {e^{ - x}} - 2x}}{{x - \sin x}}$ ની કિંમત શોધો.

$\lim _{x \rightarrow 1} \frac{a b^x-a^x b}{x^2-1} = $

જો $\alpha, \beta$ એ $x^{2}+bx+c=0$ ના ભિન્ન બીજ હોય,તો $\lim _{x \rightarrow \beta} \frac{e^{2(x^{2}+bx+c)}-1-2(x^{2}+bx+c)}{(x-\beta)^{2}}$ ની કિંમત શોધો.

$\mathop {\lim }\limits_{x \to 0} {\left\{ {\tan \left( {\frac{\pi }{4} + x} \right)} \right\}^{1/x}} = $

Vedclass Test Series

Exam Paper Generator

Online Exam Module